.39^3=p^2

Solution for .39^3=p^2 equation:

.39^3=p^2

We move all terms to the left:

.39^3-(p^2)=0

We add all the numbers together, and all the variables

-1p^2+0.059319=0

a = -1; b = 0; c = +0.059319;
Δ = b2-4ac
Δ = 02-4·(-1)·0.059319
Δ = 0.237276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.237276}}{2*-1}=\frac{0-\sqrt{0.237276}}{-2}
=-\frac{\sqrt{}}{-2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.237276}}{2*-1}=\frac{0+\sqrt{0.237276}}{-2}
=\frac{\sqrt{}}{-2}
$